Bionomial theorem/ question (wp)

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The discussion revolves around finding the value of k in the polynomial function f(x) = x^3 + 6x^2 + kx - 4, such that it yields the same remainder when divided by x - 1 and x + 2. Initial calculations led to conflicting values of k (2 and 6), prompting confusion among participants. The key resolution involves setting the remainders equal, leading to the equation 3 + k = 12 - 2k, which simplifies to k = 3. Participants emphasize the importance of correctly substituting and equating the remainders to arrive at the correct solution.
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Homework Statement




For what values of k does the function f(x)= x^3 + 6x^2 +kx -4 give the same remainder when divided by x-1 and x+2?

answer, however in the booklet it says the answer is 3, why is this? what did i do wrong?

Homework Equations





The Attempt at a Solution



So.. i set up two equations one using f(1) and one using f(-2)

f(1)= 1 + 6 + 1k -4
f(1) = -2 +k
2 = k

f(-2) = 12 -2k
2k = 12
k= 6,

I plugged 6 and 2 into the equation of f(1) and got the same (remainder of 9)

wat am i doing wrong?
 
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anyone??
 
Nelo said:
anyone??
Patience !

Please, wait at least 24 hours before bumping your thread.
 
Nelo said:

Homework Statement

For what values of k does the function f(x)= x^3 + 6x^2 +kx -4 give the same remainder when divided by x-1 and x+2?

answer, however in the booklet it says the answer is 3, why is this? what did i do wrong?

Homework Equations


The Attempt at a Solution



So.. i set up two equations one using f(1) and one using f(-2)

f(1)= 1 + 6 + 1k -4
f(1) = -2 +k This says that the remainder for f(x)/(x-1) is k - 2 .
2 = k Why do this step?

f(-2) = 12 -2k This says that the remainder for f(x)/(x+2) is 12 -2k .
2k = 12
k= 6,

I plugged 6 and 2 into the equation of f(1) and got the same (remainder of 9)

what am i doing wrong?

What does the remainder theorem say?

Set the two remainders equal to each other. Solve for k.
 
wat? like.. 6k = 2?

6/2 = 3
k=3?
 
Nelo said:
So.. i set up two equations one using f(1) and one using f(-2)

f(1)= 1 + 6 + 1k -4
f(1) = -2 +k
1 + 6 - 4 = -2?

2 = k

f(-2) = 12 -2k
2k = 12
k= 6,
Where did the f(1) and f(-2) go? This makes no sense. If you're supposed to get the same remainder when dividing by x - 1 and x + 2, then that means that
f(1) = f(-2).

And can you also please double check your work before submitting your post?
 
f(1)= 1 + 6 + 1k -4
f(1) = 7-4+1k
f(1) = 3+k
-3=k

f(-2) = (-2)^3 + 6(-2)^2 + k(-2) -4
f(-2) = 12 -2k
2k = 12
k= 6

?? what do i do now
 
Nelo said:
f(1)= 1 + 6 + 1k -4
f(1) = 7-4+1k
f(1) = 3+k
-3=k
Again, why are you making the f(1) disappear? DON'T DO THAT! :mad:

You say
f(1) = 3 + k
and
f(-2) = 12 - 2k.

Since the remainders are supposed to be equal,
f(1) = f(-2)
so substitute with the right-hand-side of the two previous equations.
 
I don't get it... substitute something that's not a full equation into the right hand side of the prev 2 eq? doesn't something have to = k inorder for me to sub it into another equation..?

How do i substitute dat
 
  • #10
Nelo said:
I don't get it... substitute something that's not a full equation into the right hand side of the prev 2 eq? doesn't something have to = k inorder for me to sub it into another equation..?

How do i substitute dat
f(1) = f(-2)
Instead of f(1), write what it equaled to.
Instead of f(-2), write what it equaled to.
That's what I meant by substituting.
 
  • #11
f(1) = 3 + k
and
f(-2) = 12 - 2k.


3+k = 12-2k
-9 = -3k
k= 3 ...

I see, thanks :P
 
  • #12
That's exactly what I suggested you do back in post #4 .
 
  • #13
gl bk
 

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