- #1
ac7597
- 126
- 6
- Homework Statement
- Use 2N3904 NPN transistors to design an amplifier which will meet the electrical specifications. Several (three) cascaded stages will be necessary.
Amplifier Specifications at 1kHz:
Zin=47k ohms minimum
Zout=4.7k ohms maximum
Overall voltage gain(no load) | Avnl |= 1000 minimum
Output voltage swing capability: at least 5V p-p without visible distortion Power supply voltage available is Vcc=15V DC
Show schematic diagram from Multisim, including reference designators and parts values. The DC voltages from a bias simulation should appear on the schematic. Do a DC bias simulation of all nodes, and then use “Place Text” to enter the values right onto the schematic at each node.
A Multisim plot of the input and output voltages when the input to the amplifier is an AC source at 1kHz with a peak-to-peak amplitude of 5mV. The output voltage should be a clean sine wave with no visible clipping or distortion. The output voltage amplitude should be clearly shown as being at least 5V peak-to-peak, thereby proving that your gain is at least the required value of |1000|.
To start:
For the initial 2N3904 parameters values use beta=150, Vbe=0.7V, ro=50k ohms.
The resistor values should be standard values that can be brought.
- Relevant Equations
- AV total= AV1 * AV2 * AV3
This cascade is divided into 3 sections thus:
the leftmost section is an emitter follower :
Ib1 = (15V-0.7V)/ ( R1 + 151R2)
IE1= 151*Ib1
re1= 26mV /(IE1)
Zb1= 150( re1+ R2)
AV1= (-150*R1)/ (R1+Zb1)
the center section is an unbiassed BJT :
Ib2 = (15V-0.7V)/ ( R3 + 151(R4+Re2a) )
IE2= 151*Ib2
re2= 26mV /(IE2)
Zb2= 150( re2+ Re2a)
AV2= (-150*R3)/ (R3+Zb2)
the rightmost section is an unbiassed BJT :
Ib3 = (15V-0.7V)/ ( Rb3 + 151(Rc3+Re3a) )
IE3= 151*Ib3
re3= 26mV /(IE3)
Zb3= 150( re3+ Re3a)
AV3= (-150*Rb3)/ (Rb3+Zb3)
AV total= AV1 * AV2 * AV3 >=1000
output voltage= AV total * (0.005V) >=5V
Is this layout correct? How do I proceed further to find the resistors?
the leftmost section is an emitter follower :
Ib1 = (15V-0.7V)/ ( R1 + 151R2)
IE1= 151*Ib1
re1= 26mV /(IE1)
Zb1= 150( re1+ R2)
AV1= (-150*R1)/ (R1+Zb1)
the center section is an unbiassed BJT :
Ib2 = (15V-0.7V)/ ( R3 + 151(R4+Re2a) )
IE2= 151*Ib2
re2= 26mV /(IE2)
Zb2= 150( re2+ Re2a)
AV2= (-150*R3)/ (R3+Zb2)
the rightmost section is an unbiassed BJT :
Ib3 = (15V-0.7V)/ ( Rb3 + 151(Rc3+Re3a) )
IE3= 151*Ib3
re3= 26mV /(IE3)
Zb3= 150( re3+ Re3a)
AV3= (-150*Rb3)/ (Rb3+Zb3)
AV total= AV1 * AV2 * AV3 >=1000
output voltage= AV total * (0.005V) >=5V
Is this layout correct? How do I proceed further to find the resistors?