Block Colliding with a Spring - Help Appreciated

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A 1.90 kg block collides with a spring (spring constant 237 N/m) and compresses it by 13.00 cm. The coefficient of kinetic friction is 0.430, which affects the work done by the spring in bringing the block to rest. The discussion emphasizes the need to account for frictional losses in the calculations. Participants suggest starting with a diagram to identify forces and using kinematics equations for accurate results. The focus is on understanding the energy transformations involved in the collision and subsequent motion.
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Homework Statement


A moving 1.90 kg block collides with a horizontal spring whose spring constant is 237 N/m.

The block compresses the spring a maximum distance of 13.00 cm from its rest position. The coefficient of kinetic friction between the block and the horizontal surface is 0.430. What is the work done by the spring in bringing the block to rest?

How much mechanical energy is being dissipated by the force of friction while the block is being brought to rest by the spring?

What is the speed of the block when it hits the spring?

Homework Equations


∆K+∆U=∆E

The Attempt at a Solution


Work done by spring = ½ * 0.430 * 0.13 ^2 and many other assorted things. None of which has been correct. Simply put, I've been firing at it in the dark.Where do I need to start?
 
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Nfinley1 said:

Homework Equations


∆K+∆U=∆E
You have left out the loss to friction.

Start by drawing a diagram and identifying the forces on the block. Then use the kinematics equations.
 
That makes sense, I just solved it all.

Thanks for the prompt response!
 
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