Block projected up inlcline with initial speed

AI Thread Summary
A block on a 40-degree inclined plane is projected upward with an initial speed of 2 m/s and a coefficient of friction of 0.05. To determine the time it takes for the block to ascend and return, the net force acting on the block must be calculated, considering both gravitational and frictional forces. The correct equations of motion involve setting the acceleration equal to the sum of forces, with attention to the direction of friction opposing motion. The friction force is directed downslope while the block moves up, requiring careful sign management in the equations. The approach to solving the problem is on the right track, focusing on these forces will yield the time needed for the block's complete motion.
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Homework Statement


I have a block on an inclined plane (the angle is 40). The block is projected with an initial speed of 2m/s and μ=0.05. I need to find the time it takes the block to go up the inclined plane and return to the point it started out.

Homework Equations

The Attempt at a Solution


I know that the force of friction will be μmgcosθ. Usually, the force bringing the block down the plane is mgsinθ.
I figure that I will need to find the acceleration and then use the equations of motion to find t, since the final speed at the top of the plane will be 0. I am having trouble setting up my equations.
Would it be that:
ma = -mgsinθ+ μmgcosθ
 
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You're on the right track. Keep in mind that friction always opposes the direction of motion. So while the block is moving upslope, friction is directed downslope as is the relevant component of the gravitational force. In other words, be careful of the signs that you apply to the friction term.
 
gneill said:
You're on the right track. Keep in mind that friction always opposes the direction of motion. So while the block is moving upslope, friction is directed downslope as is the relevant component of the gravitational force. In other words, be careful of the signs that you apply to the friction term.
Ok, I've been working on it and I think that going up the plane it will be: ma = -mgsinθ-μmgcosθ and going down the plane it would be ma=-mgsinθ+μmgcosθ since I put the axis as being x directed up the plane and y directed like the normal
 
Looks good so far!
 
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