If you are given two dice and a gameboard how would you figure out the probability of landing on each of the individual squares in one game?(adsbygoogle = window.adsbygoogle || []).push({});

Since there are two dice with 6 faces you can make a few statements without much math:

0 possibility of landing on first square,

(1/6)*(1/6) probability of landing on squares 2 and 3.

However, after that the probability of landing on a square between 4 and 12 is related to both the probability of rolling that sum as well as the probability of landing on a previous square AND rolling the subsequently necessary sum.

For example, to land on square 5 you could roll a (1,4) OR (2,3) OR {(1,1) AND (1,2)} OR {(1,2) AND (1,1)}

In the example I did not include (4,1) or (3,2) because it would have resulted in landing on the same square, yet {(1,1) AND (1,2)} would have been due to landing on square 2 and then square 5, whereas {(1,2) AND (1,1)} would have resulted in landing on square 3 and then square 5.

Which equation can you use to determine the probability of landing on each space of the board? THANK YOU for any thoughts, suggestions or resources.

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# Board game probabilities

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