Body Fall Kinematics: Find Time & Velocity at Impact

AI Thread Summary
To solve the problem of a body falling from a height of 409.5 meters under gravity, the key equations to use are s = ut + 0.5at^2 and v^2 = u^2 + 2as, with the initial velocity (u) set to zero and acceleration (a) as 9.8 m/s². The time taken to reach the ground can be calculated using the formula t = sqrt(2h/g), where h is the height and g is the gravitational acceleration. After determining the time, the velocity at impact can be found using v = gt. The discussion emphasizes the importance of understanding the equations and deriving the answers independently for better learning.
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Homework Statement


A body falls from a height of 409.5m under gravity. Determine:
(a) The time taken to reach the ground, if the initial velocity is zero
(b) The velocity at impact with ground.

Homework Equations


s= ut
v= u+at
s=ut + 0.5*at^2

The Attempt at a Solution


i tried using the formulas above but couldn't get anywhere, i guess i need to use 9.8 for the acceleration due to gravity too?
 
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Assuming air resistance is neglected you can use the constant acceleration equations to determine the answers. Read through this...it should help clarify...

http://www.pha.jhu.edu/~broholm/l3/node6.html#SECTION00020010000000000000
 
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i think I've just to use the equations above and mybe this one too: v^2=u^2+2as
 
They are the same, just different notation. The link was to help clarify how to approach the problem.

Find the time it takes for the object to hit the ground first (assuming free-fall on earth). The link will help you there.

Then use that time to determine the velocity (part b of the question).
 
BTW, don't forget that the problem states that the initial velocity is zero (it will reduce the equation a little).
 
damn, i still can't figure it out, it may be the notation that's confusing me but i don't know.
I have the info from the question: The initial velocity is 0, displacement is 409.5m(ithink)
and the acceleration is 9.8.

I just can't seem to use these values to come up with the time.
 
If you look at the first link I gave you, you'll see how this is derived (which is the most important part).

t = sqrt(2*h/g)

where,

t = time it takes for the object to reach the ground
h = the height the object is dropped from
g = gravitational accel.
 
.5 * 9.8 * t^2 = 409.5

t = squareroot(409.5/(.5*9.8))

9.8 * t = answer for b and t is the answer for a
 
  • #10
xcvxcvvc said:
.5 * 9.8 * t^2 = 409.5

t = squareroot(409.5/(.5*9.8))

9.8 * t = answer for b and t is the answer for a

The point is not to give the answer to the OP, but rather help them find it themselves so they will actually learn something.
 
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