(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Verify that the equation of the ground state energy Eo of the Bohr atom: E_{o}= (2pi^{2}e^{4}m_{e}k^{2})/h^{2}

simplifies to Eo = 13.6 eV. Show clearly how the units of the different

quantities in the equation simplify to the eV.

This is all they give. Nothing more.

2. Relevant equations

E_{o}= (2pi^{2}e^{4}m_{e}k^{2})/h^{2}

3. The attempt at a solution

m_{e}= 9.10938291 x 10^{-19}Kg

k = 1.3806488 x 10^{-23}J/K

h = 6.62606957 x 10^{-34}J.s

1.6 x 10^{-19}J = 1 eV

2 pi^{2}= 19.7392088

e^{4}= 6.589333674 x 10^{-76}C^{4}

k^{2}= 1.906195527 x 10^{-46}J^{2}/K^{2}

h^{2}= 4.390478986 x 10^{-67}J^{2}.s^{2}

when you multiply the above constants together : 2pi^{2}.e^{4}.m_{e}.k^{2}= 0 which means that the whole equation is equal to zero thus E_{o}= 0 and clearly Eo is not equal to 0 but to 13.6 eV

Also for the units I obtain for the answer when I multiply together and then divide is (C^{4}.Kg/(K^{2}.s^{2}) which is not correct and I did not see any other units for the constants we have to use.

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# Bohr Model of the Hydrogen atom: Prove that Eo = 13.6 eV

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