Boiling Point Mystery for Ethyl Alcohol

AI Thread Summary
The discussion revolves around determining the temperature at which the vapor pressure of ethyl alcohol reaches 357 mm Hg, given its normal boiling point and entropy. The original poster expresses confusion about the relationship between pressure, entropy, and phase transitions, considering the Gibbs free energy and equilibrium concepts. Participants suggest using the Clapeyron equation, which relates the change in pressure during a phase transition to temperature and enthalpy changes, which are in turn linked to entropy changes. The poster intends to share their calculations later, indicating ongoing engagement with the problem. Overall, the thread focuses on clarifying the application of thermodynamic principles to solve the boiling point mystery for ethyl alcohol.
rxrocky
Messages
3
Reaction score
0
Hello everyone!

I've encountered a small problem with one of our "special" assignments.

Question:
The normal boiling point for ethyl alcohol is 78.4 C, S for C2H5OH(g) is 282,7 J/mol*K.
At what temperature is the vapor pressure of ethyl alcohol 357 mm Hg?

Maybe I'm stupid, but I can't find a connection between the pressure and entropy. Or the phase transition. Original I thought it had something to do with Gibbs vs equilibrium, but now I'm even more confused.

I'd love to do the problem myself but I'm in need of a hint/tip :)

Thanks in advance.
 
Physics news on Phys.org
The only equation that comes to mind at the moment is some type of derivative of the Clayperon equation.
 
Yes, this is definitely a Clapeyron relation problem. The change in characteristic pressure of a phase transformation with temperature is related to the enthalpy of the transformation. And the enthalpy change is related to the entropy change. Let us know if you get stuck.
 
Thanks for the help.

I'll post my calculations later today, still not entirley sure I got it right.
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
Back
Top