Boltzmann Distribution with two gasses

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In a mixture of hydrogen and xenon gases, both gases will have the same mean kinetic energy per molecule at equilibrium due to equal temperature, specifically 3/2 kT. However, their momentum will differ, as momentum is dependent on molecular velocity, which varies significantly between the two gases due to their differing molecular weights. Hydrogen, being lighter, will have a much higher average velocity compared to xenon, but this does not translate to higher average momentum when considering the absolute values. The Boltzmann distribution for each gas will also differ, with hydrogen exhibiting a lower and broader distribution curve. Overall, while the average energy per particle remains constant across both gases, their distributions and velocities are distinct.
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What is the Boltzmann distribution look like if we have a mix of two gasses with very different molecular weights? Say hydrogen at 2 amu and xenon at 132 amu. Do they have equal average momentum and hence the hydrogen has an average velocity 66 times the velocity of the xenon and an energy .5*m*v^2 that is 66 times higher than the xenon? Or do they have equal average energy? But shouldn't they both have just .5*kT of energy per degree of freedom?
 
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edpell said:
What is the Boltzmann distribution look like if we have a mix of two gasses with very different molecular weights? Say hydrogen at 2 amu and xenon at 132 amu. Do they have equal average momentum and hence the hydrogen has an average velocity 66 times the velocity of the xenon and an energy .5*m*v^2 that is 66 times higher than the xenon? Or do they have equal average energy? But shouldn't they both have just .5*kT of energy per degree of freedom?

Since the two gases are mixed, at equilibrium they will have the same temperature and hence the same mean kinetic energy of translation. They will not have the same momentum. Molecular momentum is a function of the molecular velocity, but energy of translation is a function of the means of the squares of the velocities. The Maxwell distribution curves of their respective kinetic energies of translation will be different as well. The curve for hydrogen will be lower and broader. The mean total KE per molecule will be 3/2 kT for each gas.

In short, the KE means will be the same, the distributions will be different.
 
The Boltzmann distribution describes a statistic (mean speed) in the microcanonical ensemble. As such, particles of different kinds are non-interacting so in a mixture of two gasses, each species can be treated independently.

If you want a combined statistic for the entire gas, just add up the 2 statistics in the end using the appropriate mathematics.
 
edpell said:
What is the Boltzmann distribution look like if we have a mix of two gasses with very different molecular weights? Say hydrogen at 2 amu and xenon at 132 amu. Do they have equal average momentum and hence the hydrogen has an average velocity 66 times the velocity of the xenon and an energy .5*m*v^2 that is 66 times higher than the xenon? Or do they have equal average energy? But shouldn't they both have just .5*kT of energy per degree of freedom?

If you really mean momentum, and not absolute value of momentum, then they will have the same average momentum per particle, which will be zero. Since the absolute value of momentum is not a conserved quantity, the gases will not have the same average absolute value of momentum. Energy is conserved, so they will have the same average energy per particle.
 
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