Boltzmann equation - Why does theta = 5040/T

Physics Dad
Messages
54
Reaction score
1
Hi,

I am working on a Boltzmann equation question and I know that the solution I am looking for is that:

log(nij/nji)=log(gij/gji)-Eij(eV)(5040/T)

The only thing I don't understand is why log(e-Eij/kt) = θ = 5040/T

From what I have read in textbooks, it is just a given, but I really want to know why!

Any help gratefully received!

Thank you
 
Physics news on Phys.org
log(e-Eij /kT ) = Eij* θ where θ = log(e) / (kT) = 5040 / T when Eij is in eV
 
Thank you for the reply. It was the log(e) that was confusing me, all sorted now!
 
Hello everyone, I’m considering a point charge q that oscillates harmonically about the origin along the z-axis, e.g. $$z_{q}(t)= A\sin(wt)$$ In a strongly simplified / quasi-instantaneous approximation I ignore retardation and take the electric field at the position ##r=(x,y,z)## simply to be the “Coulomb field at the charge’s instantaneous position”: $$E(r,t)=\frac{q}{4\pi\varepsilon_{0}}\frac{r-r_{q}(t)}{||r-r_{q}(t)||^{3}}$$ with $$r_{q}(t)=(0,0,z_{q}(t))$$ (I’m aware this isn’t...
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
Back
Top