Bouncing Ball Problem, velocity vs. time

AI Thread Summary
The discussion revolves around understanding the velocity vs. time graph of a bouncing ball in a college physics context. The user seeks help identifying when the ball reaches maximum height, noting that maximum height occurs when the graph crosses zero, but not every crossing indicates maximum height. The conversation highlights the importance of analyzing the graph's slope to determine the ball's motion, with negative slopes indicating falling and positive slopes indicating rising. Clarifications are made regarding the specific times the ball hits the ground and reaches maximum height. The user acknowledges confusion but is actively engaging in problem-solving to improve their understanding.
kingneb
Messages
3
Reaction score
0
This is my first college physics class and I am feeling a little challenged, since it is the start and all. I took physics in high school and am a bit rusty. I appreciate any help.

Homework Statement



The vertical component of the velocity of a bouncing ball is shown in the graph below (graph is very large). The positive Y direction is vertically up. The ball deforms slightly when it is in contact with the ground.

[PLAIN]http://img180.imageshack.us/img180/494/graphz.png

They want for part a: Identify the instances in time where the ball is at maximum height.

Homework Equations



None really for part a. Part b asks you to calculate the average velocity while the ball is in the air. Part c, when it is on the ground. Part d asks for the maximum height above the floor using the area under the graph. So for parts b and c I guess you have to use a = v / t. I will probably need some help with these. I will continue the thread when I finish part a.

The Attempt at a Solution



I am kind of mixed up on where to start for part a. I do know the vector direction is negative where the line slopes are negative, and positive respectively. At this point I am assuming that the ball is falling when the function is below the x-axis and rising when it is above the x axis.
 
Last edited by a moderator:
Physics news on Phys.org
You're correct in that the ball is falling when the function is below the x axis

Think about what the gradient of a line at any point on the graph represents, and how this is affecting the velocity.

When the ball is at maximum height, what would the velocity at that point be?
 
So, maximum height is denoted by when the the function crosses zero?
 
That's only half correct, its not every time the function crosses zero
 
So does the ball hitting the floor happen at 1.125 seconds, 3.875 seconds?

Max Height 0 seconds, 2.25 seconds, and 5 seconds?
 
Correct
 
kingneb said:
So does the ball hitting the floor happen at 1.125 seconds, 3.875 seconds?
The ball has no velocity at t=1.125 and t= 3.375 seconds (you misread the graph on that last figure), but the ball hits the floor at 9m/s, when t=? and ?
 
Ahh yes, I was wrong with respect to that, my apologies

I was focusing too much on maximum height, and missed that error
 
Back
Top