Bowling Ball Return

  • Thread starter scheng12
  • Start date
  • #1
3
0

Homework Statement



A bowling ball encounters a h = 0.662 m vertical rise on the way back to the ball rack, as the figure below illustrates.

Ignore frictional losses and assume that the mass of the ball is distributed uniformly. The translational speed of the ball is 3.70 m/s at the bottom of the rise. Find the translational speed at the top.

Homework Equations



KE= 1/2mv^2

U=mgh

Conservation of energy and momentum?


The Attempt at a Solution


I tried basic conservation of energy but that didn't really work out. I'm not sure where to start on this one since it doesn't give the mass of the ball. Though that probably cancels out anyway. When I set KE = U the answer is incorrect. I'm not sure on what else I can do.
 

Answers and Replies

  • #2
minger
Science Advisor
1,495
2
The initial kinetic energy is not equal to the change in potential energy. The initial energy is equal to the change in potential energy plus the final kinetic energy.
(KE + U)_1 = (KE + U)_2
 
  • #3
3
0
So:

1/2mvi2=mgh + 1/2mvf2?


When I plug in the values for this the answer is incorrect as well.
 
  • #4
minger
Science Advisor
1,495
2
The answer is not 0.837 m/s?
 

Related Threads on Bowling Ball Return

  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
13
Views
8K
  • Last Post
Replies
4
Views
12K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
3
Views
5K
  • Last Post
Replies
3
Views
3K
  • Last Post
Replies
11
Views
3K
  • Last Post
Replies
2
Views
2K
Top