(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A ball rolls down a roof that makes an angle of 30 degrees to the horizontal. It rolls

off the edge woth speed of 5.00 m/s. The distance to the ground from that point is 7.00 m.

a) How long is the ball in the air for?

b) How far from the base of the house does it land?

c) What is its speed before landing?

2. Relevant equations

[tex]\vartheta[/tex] = 30 degrees

speed = 5.00 m/s

distance from ground to point ball being dropped (roof) = 7.00 m

3. The attempt at a solution

a) time in the air:

y = -7.00m

v_{x0}=5.00 m/s

a_{x}= 0 <- drop so acceleration is 0..correct?

v_{y0}= 0

a_{y}= -g <---gravity

x_{0}and y_{0}= 0

y = - 1/2 gt^{2}

t = sqrt [(2y)/(-g) = sqrt [(2)(-7.00)/(-9.80) = 1.2 s <--ball in the air for

b) far from the base of the house:

x = v_{x0}t = (5.00)(1.2) = 6 m<---- distance from base of the house

c) i dont know how to find the speed-do i need the angle in this equation?

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# Homework Help: Bowling Ball Thrown off Building-Check my work/solutions pls.

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