Box on Inclined Plane (with Friction)

AI Thread Summary
To determine the speed of a crate being pulled up an incline with friction, it's essential to account for all forces acting on the crate, including friction and the gravitational component. The work done by the pulling force is calculated as 543.4 J, but this does not represent the total work affecting the crate's kinetic energy. The change in kinetic energy must be considered, factoring in the work done against friction and gravity. The initial speed of the crate is 1.52 m/s, and the final speed calculation must include these additional forces to arrive at the correct answer. Properly applying the work-energy principle will yield the accurate speed after being pulled 4.94 m.
B. variegatus
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Homework Statement


A crate of mass 9.2 kg is pulled up a rough incline with an initial speed of 1.52 m/s. The pulling force is 110 N parallel to the incline, which makes an angle of 20.6° with the horizontal. The coefficient of kinetic friction is 0.400, and the crate is pulled 4.94 m.

(e) What is the speed of the crate after being pulled 4.94 m?

Homework Equations


F(f)=mu*N
E(k)=(mv^2)/2
U=mgh
delta E(k)= E(k1) - E(k2)
W=F*d
d=(a*t^2)/2

The Attempt at a Solution


W=(m*v(f)^2)/2
v(f)=sqrt(2W/m)
W=110*4.94=543.4J
v(f)=sqrt(543.4*2/9.2)=10.87ms^-1

The computer says that this is wrong though?
 
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B. variegatus said:

Homework Statement


A crate of mass 9.2 kg is pulled up a rough incline with an initial speed of 1.52 m/s. The pulling force is 110 N parallel to the incline, which makes an angle of 20.6° with the horizontal. The coefficient of kinetic friction is 0.400, and the crate is pulled 4.94 m.

(e) What is the speed of the crate after being pulled 4.94 m?

Homework Equations


F(f)=mu*N
E(k)=(mv^2)/2
U=mgh
delta E(k)= E(k1) - E(k2)
W=F*d
d=(a*t^2)/2

The Attempt at a Solution


W=(m*v(f)^2)/2
v(f)=sqrt(2W/m)
W=110*4.94=543.4J
v(f)=sqrt(543.4*2/9.2)=10.87ms^-1

The computer says that this is wrong though?
total work is change in KE. You just gave the final,not the change. Also, more forces besides the applied force do work. You need to identify work done by all forces.
 
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