Understanding Bragg's Law and Reflection: A Beginner's Guide

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Bragg's Law explains how x-rays are diffracted when they scatter off a crystal lattice, resulting in intensity peaks at specific angles. The law states that the angle of incidence equals the angle of reflection, and constructive interference occurs when the path length difference between scattered rays is an integral multiple of the x-ray wavelength. This principle allows for the determination of atomic or molecular structures within crystals. While electric dipole moments are mentioned in advanced studies, they are not essential for understanding Bragg's Law at a beginner level. Overall, the discussion clarifies the basic concepts of x-ray diffraction and Bragg's Law for first-year undergraduates.
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I don't think I understand Bragg's law, but I'd quite like to! There's loads of stuff online, but most of it is too complicated for me as a first year undergrad. My understanding was that x-rays get diffracted, but then my textbook says something about electric dipole moments (never heard of them) and makes it sound like the wave is actually incident on the atoms. Apparently it's not the same as a diffraction grating at all.
There wasn't really a question there... I'm just quite confused! I'd appreciate any help :)
 
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whatisreality said:
I don't think I understand Bragg's law, but I'd quite like to! There's loads of stuff online, but most of it is too complicated for me as a first year undergrad. My understanding was that x-rays get diffracted, but then my textbook says something about electric dipole moments (never heard of them) and makes it sound like the wave is actually incident on the atoms. Apparently it's not the same as a diffraction grating at all.
There wasn't really a question there... I'm just quite confused! I'd appreciate any help :)

Your understanding that x-rays get diffracted is correct. yes, It is similar to diffraction grating. All that business about electric dipole moments is for later years, trying to explain the underlying physics.

Bragg's Law -
Bragg found that when x-rays are scattered from a crystal lattice, the scattering gives rise to peaks of scattered intensity observed in certain directions which meet the following conditions:
  1. The angle of incidence of the x-rays = angle of reflection of the scattered x-rays.
  2. When the path length difference between rays scattered by successive planes of the lattice is equal to an integral number of wavelength of the incident x-rays, the rays interefere constructively to produce peaks of intensity.
The condition for maximum intensity is known as Bragg's law which allows us to calculate the atomic or molecular structure of the atoms or molecules constituting the crystal lattice. Bragg’s Law: n λ = 2d sin θ

Hope the above makes sense to you?

upload_2015-2-10_15-2-59.png
 
n*(lambda)=2dsin(theeta) which is braggs eqn
 
Nainam said:
Your understanding that x-rays get diffracted is correct. yes, It is similar to diffraction grating. All that business about electric dipole moments is for later years, trying to explain the underlying physics.

Bragg's Law -
Bragg found that when x-rays are scattered from a crystal lattice, the scattering gives rise to peaks of scattered intensity observed in certain directions which meet the following conditions:
  1. The angle of incidence of the x-rays = angle of reflection of the scattered x-rays.
  2. When the path length difference between rays scattered by successive planes of the lattice is equal to an integral number of wavelength of the incident x-rays, the rays interefere constructively to produce peaks of intensity.
The condition for maximum intensity is known as Bragg's law which allows us to calculate the atomic or molecular structure of the atoms or molecules constituting the crystal lattice. Bragg’s Law: n λ = 2d sin θ

Hope the above makes sense to you?

View attachment 78914
Thank you, that's a really good summary, definitely makes it clearer! I'll ignore dipoles for now then :)
 
That is reality for whatisreality! I am glad you liked my explanation.
 
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