Brass Compression: Solving For ΔL

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A 1.8-meter brass bar with a square cross-section of 1.3 cm is compressed by a force of 9.0×10^3 N. The calculation for the change in length (ΔL) uses Young's Modulus, resulting in a shortening of approximately 0.0011 m. Although the calculated answer was slightly off from the online homework program's accepted value of 0.00105 m, it was confirmed to be correct. The discrepancy arose due to the program's rounding or precision requirements. Accurate calculations are essential for proper acceptance in online homework systems.
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Homework Statement



A 1.8- m long brass bar has a square cross section 1.3 cm on an edge. The bar is compressed by a force of 9.0×10^3 N applied to its ends. By how much does the bar shorten (in m)?

Homework Equations



There is an example in our book explaining how to use a variation of Young's Modulus. ΔL = FL/YA

The Attempt at a Solution



Change 1.3 cm into .013 m.

(9.0x10^3 N)(1.8m) / (91 x 10^9 N/m^2)(.013^2) = .0011 m

I squared .013 since it's the area squared.. and the 91 x 10^9 is the value for brass in the Elastic Moduli.

Of course this is wrong, but not sure what I'm not doing quite right.
 
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Nevermind guys, that turned out to be the CORRECT answer.

The online Homework program had the answer listed as .00105 m

Since I was putting .0011 in it did not accept my answer. Go figure *sigh*
 
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