Brave Fish launching himself in a cannon

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The discussion focuses on a physics problem involving a fish launching from a 6 cm cannon at a speed of 6.5 m/s. The calculations reveal that the acceleration during the launch is approximately 352.08 m/s², leading to a time of 0.02 seconds for the fish to exit the cannon. An alternative method for calculating time is suggested, using the average velocity formula instead of incorporating gravitational acceleration. The conversation emphasizes the importance of correctly applying physics equations to solve motion problems. Overall, the analysis provides insights into projectile motion and the application of kinematic equations.
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Homework Statement


The brave fish launches himself from a 6 cm cannon straight up in the air. When he leaves the cannon he is traveling at 6.5 m/s. assume constant acc while in the cannon.
How long was the fish in the cannon?



Homework Equations


v^2=Vo^2+2ax
X= Xo + Vot + 1/2at^2
X=height
Xo=initial height
Vo=initial velocity
t=time



The Attempt at a Solution


6.5^2=0^2+2a(.06)
a=352.08m/s^2
352.08=u-9.8 (u=up acc)
u=361.88m/s^2

x=1/2at^2
.06=1/2(361.88)t^2
t=.02sec
 
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Yes, but do not add 'g' to the acceleration. You can get the same result more easily by using x = [(v_o + v_f)/2]t.
 
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