Bremsstrahlung from different materials

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Bremsstrahlung can occur when charged particles collide with any matter, not just metals, challenging previous assumptions. Heavy, high-Z materials like metals produce more intense bremsstrahlung due to faster particle deceleration. To minimize bremsstrahlung, whipple shields and particle shields should ideally be constructed from lighter, low-Z materials such as polymers. This approach could enhance shielding effectiveness against high-energy radiation. Understanding these material properties is crucial for effective particle shielding design.
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I'm curious about the compatibility of a whipple shield and bremsstrahlung prevention(like that provided by paraffin). Until a short time ago, I was under the impression that bremsstrahlung is only generated when a charged particle collides with a metal. This is apparently not the case.

So under what conditions is bremsstrahlung not generated, so I understand what my whipple shield and particle shielding need to be made of??
 
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Bremsstrahlung is generated when charged particles hit any kind of matter.

Heavy high-Z atoms such as metals, however, will lead to faster deceleration and thus more and harder (higher energy=more difficult to shield) Bremsstrahlung.

My guess is that your whipple shield and particle shield should be made out of light, low-Z materials such as polymers.
 
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