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I trying to build an magnet which can pull an object with 5N..

I am using S37 as my the iron for my horseshoe magnet,

And been using this formula to convert Newtonian Force to magnetic force

[itex]\vec{F}=\frac{B}{µ0}*A[/itex]

A= cross sectional area = 0,002*1/100 M^2

B = Magnetic Force

µ0(permeability in vacuum) = 4[itex]\pi[/itex]*10^-17

B_gap(x) =[itex]\frac{µ0*I*N}{\frac{l_j}{µj}+2x}[/itex]

l_j: the length of horseshoe = 2 CM

µj: permeability of Steel37.. Can't find it using google.. :(

x: airgap distance between each legs and the materiel it should attract. = 0,002m

I am using 1 A, I tested my calctulation with 3N, which using my calculation says that i need 600 windings, but i seem to extreme..

The reason why i think this is not true is because 600 winding => 2 (0.002 + 0.01)*600 M copper wire=> R=0,079 ohm => V =0,079V..

Is it too extreme?

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# Building an electro magnet

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