Bullet passing through 4cm thick board

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A bullet traveling at 350 m/s passes through a 4 cm thick board and exits at 210 m/s. The relevant equation for this scenario is d = 0.5(vo + vf)t, where d is the thickness of the board, vo is the initial speed, and vf is the final speed. The thickness must be converted from centimeters to meters for accurate calculations. The discussion highlights the need to determine the time taken for the bullet to pass through the board, with participants confirming the correct approach to the problem. Understanding the variables in the equation is essential for solving the time calculation.
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Homework Statement



A bullet traveling horizontally at a speed of 350 m/s hits a board perpendicular to the surface, passes through it, and it emerges on the other side at a speed of 210 m/s. If the board is 4 cm thick, how long does the bullet take to pass through it (in seconds)?


Homework Equations



X(t) = Vt + x(i)


The Attempt at a Solution



My problem is not knowing which formula to use. Thank you
 
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if you consider that the acceleration of the bullet is constant in the board. than, i think you can handle it.
 
First off, deceleration is constant, if the board is uniform.
The equation you use is d=.5(vo+vf)t. d, vo, vf is given. Also, don't forget to convert cm to m.
 
Thank you very much, Silvashadow
 
Did I get it right?
 
Yes, I got it right! In the future I will remember to mention that.

Also, would you please see my other thread (titled “angle of bullet when fired”) and let me know if I am on the right track for answering the question.

FYI, there is no additional information to the problem (titled “angle of bullet when fired”), other than what was stated. Thank you

The possible answers for the problem (titled “angle of bullet when fired”), are 3, 10, 30 and 80.
 
Ive been looking at this problem for a few minutes.
What does the d stand for in the forumla that silvashadow mentions?

i get that d=.5(350+210)t where t is what we are looking for. is d 4?
 
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