Bullet striking a block on a frictionless surface

AI Thread Summary
A 10g bullet traveling at 1000 m/s strikes a 100g block at rest, and the combined velocity after the collision is calculated using conservation of momentum, yielding v_f = 1000/11 m/s. The discussion raises questions about applying conservation of energy, noting that kinetic energy is not conserved in inelastic collisions, as some energy transforms into heat. The potential energy of the block remains unchanged, while kinetic energy decreases post-collision. Participants emphasize that total energy must be calculated in joules, focusing solely on kinetic energy after the impact. The conclusion is that conservation of energy cannot be used to solve this problem effectively.
Dustinsfl
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Homework Statement


A 10g bullet with velocity 1000m/s strikes a 100g block at rest. What is their combined velocity? Can you work the problem with conservation of momentum? Energy?


Homework Equations





The Attempt at a Solution


For conservation of momentum, we have
$$
10g\cdot 1000m/s + 100g\cdot 0m/s = 110gv_f\Rightarrow v_f = \frac{1000}{11}m/s.
$$
How is this done with the conservation of energy? The KE right after impact is ##55g\cdot v_f^2 = ?##
Am I using the 0 PE level of the block? If that is the case, I have ##(m+M)gh=110g\cdot 9.8m/s^2\cdot h##. What is ##h##? I have two unknowns then.
 
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Dustinsfl said:

Homework Statement


A 10g bullet with velocity 1000m/s strikes a 100g block at rest. What is their combined velocity? Can you work the problem with conservation of momentum? Energy?


Homework Equations





The Attempt at a Solution


For conservation of momentum, we have
$$
10g\cdot 1000m/s + 100g\cdot 0m/s = 110gv_f\Rightarrow v_f = \frac{1000}{11}m/s.
$$
How is this done with the conservation of energy? The KE right after impact is ##55g\cdot v_f^2 = ?##
Am I using the 0 PE level of the block? If that is the case, I have ##(m+M)gh=110g\cdot 9.8m/s^2\cdot h##. What is ##h##? I have two unknowns then.

Why are you bringing gravity into this? What happens if the block is sliding on a long flat surface after it is struck by the bullet?

What happens to the KE of the bullet after it strikes the block?

What happens to the KE of the block after it is struck by the bullet?
 
SteamKing said:
Why are you bringing gravity into this? What happens if the block is sliding on a long flat surface after it is struck by the bullet?

What happens to the KE of the bullet after it strikes the block?

What happens to the KE of the block after it is struck by the bullet?

It is an inelastic collision so the KE is ##55gv_f^2## directly after impact. I already stated this though.
 
Dustinsfl said:
How is this done with the conservation of energy? The KE right after impact is ##55g\cdot v_f^2 = ?##
Am I using the 0 PE level of the block? If that is the case, I have ##(m+M)gh=110g\cdot 9.8m/s^2\cdot h##. What is ##h##? I have two unknowns then.

The mechanical energy (kinetic+potential energy) is not conserved. The potential energy does not change, the kinetic energy decreases, as part of the initial energy transforms to heat.

ehild
 
ehild said:
The mechanical energy (kinetic+potential energy) is not conserved. The potential energy does not change, the kinetic energy decreases, as part of the initial energy transforms to heat.

ehild

How am I supposed to use this information here?
 
Dustinsfl said:
How am I supposed to use this information here?

It means you cannot solve the problem assuming conservation of energy. You have to calculate the total energy after the collision, in joules. The total energy is solely kinetic. What does "g" mean in your formula?


ehild
 
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