Bungee Cord Force Constant from Work?

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SUMMARY

The discussion focuses on calculating the force constant of a bungee cord used by a jumper with a mass of 61 kg. The jumper descends 42.9 m below the bridge, and the bungee cord, which is 25 m long, behaves like a spring beyond that length. The calculations reveal that the work done by gravity is 25646 J, leading to a force of -1433 N and a calculated force constant of k = 80 N/m. The conclusion indicates that this value is likely incorrect due to a misunderstanding of the spring force behavior.

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  • Understanding of gravitational force and work (W = F X d)
  • Knowledge of Hooke's Law (F = -kx)
  • Basic principles of energy conservation in mechanics
  • Familiarity with the concept of net work and its implications
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  • Review the principles of Hooke's Law and its application in spring systems
  • Study energy conservation in mechanical systems, particularly in elastic potential energy
  • Learn about the dynamics of bungee jumping and the forces involved during free fall
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Homework Statement


A bungee jumper jumps with a mass of 61kg jumps off of a bridge. The massless bungee cord is 25m long and beyond that length acts as a spring. The jumper reaches the lowest point 42.9m below the bridge. Find the force constant which characterizes the bungee cord.

Homework Equations


W = F X d
F = -kx

The Attempt at a Solution


First I calculated the work for mg.
Wmg = 42.9 * 61(9.8) = 25646J

Since the object stops, the object has a net work of zero. So:
-25646 = 17.9 * F
F = -1433N

-1433 = -k(17.9)
k = 80N/m.

This seems far too low, could someone please tell me where my logic is flawed? I think it might be In the assumption that balancing net work accounts for the object stopping but i am not sure.

Thanks in advance!
 
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The force exerted by a spring is not constant, as you assumed.

ehild
 

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