Calc Centripetal Acceleration: Rotational Motion & Vinyl Record Player

AI Thread Summary
The discussion centers on calculating the centripetal acceleration of a point on the edge of a vinyl record player, which rotates with a period of 3.6 seconds and has a radius of 8.89 cm. The user correctly converted the radius to meters and is attempting to find the velocity needed to calculate centripetal acceleration using the formula Ac = v^2/r. They confirm that the point travels a distance of 2π in 3.6 seconds, leading to confusion about how to derive the velocity from this information. The circumference of the circle, calculated as 0.1778 meters, is essential for determining the velocity, but the user expresses uncertainty about its application in the calculations.
nbroyle1
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In the days before compact discs and MP3 players (ancient history!), music was recorded in scratches in the surface of vinyl-coated disks called records. In a typical record player, the record rotated with a period of 3.6 s. Find the centripetal acceleration of a point on the edge of the record. Assume a radius of 8.89 cm.

So I already converted the radius to meters and got .0889m.

Now I need to find the velocity in order to plug it into the equation for centripetal acceleration which is Ac=v^2/r...

How should I go about solving for the velocity so I can get the centripetal acceleration??
 
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nbroyle1 said:
In the days before compact discs and MP3 players (ancient history!), music was recorded in scratches in the surface of vinyl-coated disks called records. In a typical record player, the record rotated with a period of 3.6 s. Find the centripetal acceleration of a point on the edge of the record. Assume a radius of 8.89 cm.

So I already converted the radius to meters and got .0889m.

Now I need to find the velocity in order to plug it into the equation for centripetal acceleration which is Ac=v^2/r...

How should I go about solving for the velocity so I can get the centripetal acceleration??
What distance does that point on the edge travel in one second?
 
im not sure... So its traveling 2∏ in 3.6s right??
 
nbroyle1 said:
im not sure... So its traveling 2∏ in 3.6s right??

Yes.

Then, how far does the point on the edge travel in 3.6 seconds?
 
360 degrees. So then in one second I think it travels 100 degrees??
 
So I found that the acceleration is 1.745rad/s^2. Then I plugged it into the equation for average acceleration to find the velocity and got 6.28m/s... is this correct??
 
nbroyle1 said:
So I found that the acceleration is 1.745rad/s^2. Then I plugged it into the equation for average acceleration to find the velocity and got 6.28m/s... is this correct??
I don't think so.

What is the circumference of the circle made by the point on the edge?
 
.1778m is the circumfrance
 
how does the circumference help me I am confused??
 
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