Calc II Y = (a^2 - x^2)^(1/2)

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In summary, the conversation revolved around finding the surface area when Y = (a^2 - x^2)^(1/2) is revolved around the x-axis. The participants discussed the geometric implications of the equation and the importance of understanding arc length and surface area formulas. They also suggested examining the relationship between y = (a^2 - x^2)^(1/2) and y^2 + x^2 = a^2 to gain a better understanding of the problem.
  • #1
calc II
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?Find the surface area when Y = (a^2 - x^2)^(1/2) is revolved around the x-axis?

?Geometrically, what have you found?

Please help. Thank you.
 
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  • #2
Could you show us what you have tried? It might give us an idea on where you need help.

Also, there is a template for homework posts. For future reference, please use it. It should appear by default whenever you start a new topic in the homework section.
 
  • #3
Char. Limit said:
Could you show us what you have tried? It might give us an idea on where you need help.

Also, there is a template for homework posts. For future reference, please use it. It should appear by default whenever you start a new topic in the homework section.

I just need help on how to set up the problem. (And i'll definitely use the template next time)
 
  • #4
Well, firstly, how well do you know arc length? Because it will be needed here...

And tell me, how would you find the surface area of a regular solid, like say a cylinder, that has no top or bottom to consider?

Your equation in a more elegant format:

[tex]y=\sqrt{a^2-x^2}[/tex]
 
  • #5
calc II said:
?Find the surface area when Y = (a^2 - x^2)^(1/2) is revolved around the x-axis?

?Geometrically, what have you found?

Please help. Thank you.

Your equation [tex]y=\sqrt{a^2-x^2}[/tex] may be more recognizable in the form [itex]y^2+x^2=a^2[/itex]. What shape does the graph of this equation have? Can you deduce how [tex]y=\sqrt{a^2-x^2}[/tex] relates to [itex]y^2+x^2=a^2[/itex]? This should help with the second question (and also give you an idea of what to expect for the answer to the first question). As Char.Limit pointed out, a good look at the arc length and surface area formulas might be in order.
 

1. What is the formula for calculating the derivative of Y = (a^2 - x^2)^(1/2)?

The derivative of Y = (a^2 - x^2)^(1/2) is given by (a^2 - x^2)^(-1/2) * (-2x).

2. How do I find the indefinite integral of Y = (a^2 - x^2)^(1/2)?

The indefinite integral of Y = (a^2 - x^2)^(1/2) is given by (1/2) * (a^2 - x^2)^(3/2) + C.

3. What is the domain and range of Y = (a^2 - x^2)^(1/2)?

The domain of Y = (a^2 - x^2)^(1/2) is all real numbers between -a and a, and the range is all real numbers between 0 and a.

4. Can the graph of Y = (a^2 - x^2)^(1/2) be shifted or translated?

Yes, the graph of Y = (a^2 - x^2)^(1/2) can be shifted or translated by adding or subtracting a constant value to the expression. This will shift the graph horizontally.

5. How can I use Y = (a^2 - x^2)^(1/2) to find the area under a curve?

To find the area under a curve represented by Y = (a^2 - x^2)^(1/2), you can use the definite integral formula with appropriate limits of integration. This will give you the area between the curve and the x-axis.

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