Calc Mass Calcium Carbonate Precipitating

  • Thread starter Thread starter steven chanza
  • Start date Start date
  • Tags Tags
    Mass
AI Thread Summary
To calculate the mass of calcium carbonate precipitate formed from mixing sodium carbonate and calcium nitrate, first, write the balanced reaction equation: Na2CO3 + Ca(NO3)2 → CaCO3 + 2NaNO3. Determine the moles of sodium carbonate by multiplying its concentration (0.2000 mol/L) by its volume (0.10000 L), resulting in 0.02000 moles. For calcium nitrate, multiply its concentration (0.1000 mol/L) by its volume (0.20000 L), yielding 0.02000 moles. Since the reaction has a 1:1 molar ratio, both reactants will completely react, producing 0.02000 moles of calcium carbonate, which can be converted to mass using its molar mass (100.09 g/mol), resulting in 2.002 grams of precipitate. This calculation illustrates the stoichiometric relationships in the reaction.
steven chanza
Messages
1
Reaction score
1
A solution of 100.00mL of 0.2000mol/L sodium carbonate and 200.00mL of 0.1000mol/L calcium nitrate solutions are mixed together according to the reaction: sodium carbonate + calcium nitrate→ calcium carbonate + sodium nitrate. how would you calculate the mass of calcium carbonate that would precipitate?
 
  • Like
Likes Chisha
Chemistry news on Phys.org
Start with the balanced reaction equation. How many moles of sodium carbonate? Of calcium nitrate? This is simple stoichiometry and conversion between concentration, volume, number of moles and mass.

Note you should show your attempts at solving the question to receive help. This is a forum policy.
 
It seems like a simple enough question: what is the solubility of epsom salt in water at 20°C? A graph or table showing how it varies with temperature would be a bonus. But upon searching the internet I have been unable to determine this with confidence. Wikipedia gives the value of 113g/100ml. But other sources disagree and I can't find a definitive source for the information. I even asked chatgpt but it couldn't be sure either. I thought, naively, that this would be easy to look up without...
I was introduced to the Octet Rule recently and make me wonder, why does 8 valence electrons or a full p orbital always make an element inert? What is so special with a full p orbital? Like take Calcium for an example, its outer orbital is filled but its only the s orbital thats filled so its still reactive not so much as the Alkaline metals but still pretty reactive. Can someone explain it to me? Thanks!!

Similar threads

Back
Top