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Calc vertice problem

  1. Jun 25, 2011 #1
    1. The problem statement, all variables and given/known data

    One vertice is the closest point to a focus in an ellipse. For instance take

    [tex]\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1[/tex] with a > b > 0 and one focus at (c,0) and one vertice at (a,0), is (a,0) the closest point on the ellipse to the focus (c,0)?


    2. The attempt at a solution

    This is true right?
     
  2. jcsd
  3. Jun 25, 2011 #2

    HallsofIvy

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    Staff Emeritus
    Science Advisor

    Yes, that is true. And the other vertex, (-a, 0) is the point farthest from the focus.

    By the way, the singular of "verices" is "vertex", not "vertice".
     
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