Calcualte water discharge of a pipeline at different heights

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SUMMARY

The discussion focuses on calculating the water discharge of an 8 km pipeline transporting water from a reservoir at 500 m to a water treatment facility at 425 m. Using Bernoulli's equation and mass conservation principles, the initial calculations indicated a velocity of 54.24 m/s, but the correct discharge velocity is 38.36 m/s, leading to a final discharge of 1.525 m³/s. The user, escobar147, highlights potential errors in the pressure calculations for both the inlet and outlet, prompting a request for clarification on these computations.

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Engineers, hydrologists, and students in fluid mechanics who are involved in pipeline design, water resource management, or hydraulic calculations will benefit from this discussion.

escobar147
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A pipeline is 8 km long and is required to convey water from a reservoir, at 500 m
above datum, to the intake of a water treatment works at 425 m above datum. If
the pipe has a diameter of 225 mm, what is the discharge of water through the
pipe? The density of water is 1000 kg/m3.

relevant equations:

bernoullis Energy Conservation:

P1/ρg + u1^2/2g + z1 = p2/ρg + u2^2/2g + z2

mass conservation equation:

U1A1 = U2A2

Q1 = Q2




The Attempt at a Solution



U1 = 0 Since the resovoir is stationary,

p1 = ρgh p2 = ρgh

putting values into bernoullis:

4905000/9810 + 500 = 4169250/9810 + u2^2/19.62 + 425


150 = u2^2/19.62

u2^2 = 2943
√2943 = 54.24 m/s

at this point the answer should be: 38.36 m/s

and the final answer should be: Q = 1.525m^3/s

i am completely lost, any help would be massively appreciated!
 
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escobar147: What is the reservoir depth at the pipe inlet? And what is the reservoir depth (if any) at the pipe outlet? It currently appears you made a mistake in computing either pressure p1 or p2, or on both p1 and p2. Show how you computed p1 and p2, and why?
 

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