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An event has an 8% chance to occur per try. How would I calculate the chance of the event occurring at least once after 3 tries?
Drakkith said:An event has an 8% chance to occur per try. How would I calculate the chance of the event occurring at least once after 3 tries?
The formula for calculating the 8% chance of an event occurring after 3 tries is 1 - (1 - 0.08)^3. This equation takes into account the probability of the event not occurring (1 - 0.08) and raises it to the power of the number of tries (3), then subtracts that value from 1 to get the probability of the event occurring at least once.
Yes, the 8% chance of an event occurring after 3 tries can be converted to a decimal by dividing 8 by 100, which equals 0.08. To convert to a percentage, simply multiply the decimal by 100, which would give you 8%.
Yes, the formula for calculating the 8% chance of an event occurring after a different number of tries is 1 - (1 - 0.08)^n, where n is the number of tries. This formula can be used to calculate the probability of an event occurring after any number of tries.
The probability of the event occurring on the first try is 8%. This is because the formula for calculating the chance of an event occurring after one try is simply 0.08 (or 8%), since there is no need to raise it to a power or subtract it from 1.
No, the 8% chance of an event occurring after 3 tries cannot be used to predict the exact outcome of the event. It only gives us the probability of the event occurring at least once, not the specific outcome. Other factors, such as the nature of the event and any additional information, would need to be taken into account to make a more accurate prediction.