Calculate angle as a function of time

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SUMMARY

The discussion focuses on calculating the angle of a rigid body under constant angular velocity, specifically using the formula θ=ωt=[RPM]2πt/60. The angular velocity is derived from the known RPM, where ω=2πf. To ensure the angle resets after a full rotation, the calculation incorporates the modulus operation, resulting in θ=(2π⋅frac([RPM]t/60)). This approach effectively provides the basic angle in radians, accounting for continuous rotation.

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  • Understanding of angular velocity and its calculation
  • Familiarity with radians and the concept of modulus
  • Basic knowledge of rigid body dynamics
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LizardCobra
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I need to calculate the angle of a rigid body under constant angular velocity as a function of time. The RPM of the body is known, so the angular velocity is ω=2πf. Therefore θ=ωt=[RPM]2πt/60. How can I calculate the angle so that it 'resets' after a full rotation?
 
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θ=ωt=[RPM]2πt/60 is correct. If you want the "basic" angle it is (θ mod 2π) = 2π⋅([RPM]t/60 mod 1) = 2π⋅frac([RPM]t/60) (frac means the decimal part).
 

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