Calculate Bending Moment of Wooden Joist - 1.0 & 2.0 m

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SUMMARY

The discussion focuses on calculating the bending moment of a wooden joist with a rectangular cross-section spanning 5.0 m and supporting a 30 kN load positioned 3.0 m from the right end. The joist has a depth of 150 mm and a maximum tensile strength of 12 MPa. Participants recommend using the formula M/I = sigma/y = E/R and suggest starting with a free-body diagram to determine reaction loads before proceeding with the calculations.

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  • Understanding of bending moment calculations
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  • Knowledge of material properties, specifically tensile strength
  • Basic grasp of structural engineering principles
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This discussion is beneficial for civil engineers, structural engineers, and students studying structural analysis, particularly those focused on wooden structures and bending moment calculations.

barnacksam
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3) A wooden joist of rectangular cross-section spans a gap of 5.0 m and supports a load of 30 kN placed 3.0 m from the right-hand end. The joist has a depth of 150 mm and the maximum tensile strength that it is allowed to withstand is 12 MPa.

a) Calculate the bending moment 1.0 m and 2.0 m from the right-hand end.



M/I = sigma/y = E/R

Have no clue, cheers
 
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Recommend starting with a free-body diagram, then finding the reaction loads.
 

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