Calculate change in air pressure (Physics 101 type Q)

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Discussion Overview

The discussion revolves around calculating the change in air pressure within a long tube, specifically in the context of a gas station driveway hose being compressed by a vehicle. Participants explore the relationship between volume reduction and pressure increase, considering factors such as temperature and potential leaks.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Exploratory

Main Points Raised

  • One participant describes the setup of a gas station hose and attempts to calculate the change in air pressure when the hose is compressed by a vehicle.
  • Another participant states that at constant temperature, the product of pressure and volume remains constant, suggesting that a 10% decrease in volume results in a 10% increase in pressure.
  • A participant calculates that a 5.1% decrease in volume would lead to an increase of approximately 0.76 PSI, based on an initial pressure of 15 PSI.
  • One participant emphasizes the importance of measuring the rate of change of pressure to account for variations in absolute pressure due to temperature changes or leaks.

Areas of Agreement / Disagreement

Participants generally agree on the relationship between volume reduction and pressure increase, but there is no consensus on the correctness of the specific calculations or the implications of external factors like temperature and leaks.

Contextual Notes

Participants acknowledge that the calculations depend on assumptions such as constant temperature and the specific conditions of the hose compression. The discussion does not resolve the potential impact of these factors on the final outcome.

rdy4trvl
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I'd like to calculate the change in air pressure within a long tube - like the driveway hoses at gas stations.

The static pressure is zero, a vehicle drives over the hose and the increase in pressure activates a switch. I'm trying to determine the proper switch size (in PSI).

So, here is my attempt to start solving this (simple) problem...
  • The hose is 1/2" (interior diameter) by 20 feet long. I calculate the cubic inches to be 47.1 (3.14 x 1/4 x 1/4 x 240 inches).
  • If a vehicle drives over the hose, (say 12" of hose is compressed flat, for simplicity), then the cubic inches become 44.7 (3.14 x 1/4 x 1/4 x 228 inches). (If the two wheels don't hit at the same time, this could certainly change the results...but let's just keep it simple for now - one wheel, evenly compressed hose.)
  • Volume of air decreases from 47.1 cubic in (CI) to 44.7 CI...how is this converted to a change in air pressure (assuming 47.1 was at 0 PSI)?

Thanks
 
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At constant temperature the pressure * volume stays the same.
So if you decrease the volume by 10% the pressure goes up by 10%.

ps. The pressure in the pipe is 15psi - the same as outside air.
The 'gauge pressure' (PSG), ie the extra internal pressure, is zero.
 
Just to make sure I got this right...
In my example, the volume (of air in a tube capped at both ends) decreases from 47.1 to 44.7 or 5.1%...
Then the pressure would have increased 0.76 PSI (15PSI x 5.1%)
And I would need a switch able to detect < 1PSI increase in pressure.
...sounds logical...is it correct?
 
Correct
Ideally you would like to measure a rate-of-change of pressure, then you don't have to worry about the absolute pressure in the pipe changing with temperature or slow leaks etc.
The change in pressure with time as a car rolls over it should be pretty noticeable.
 
Great!
Thanks for the help...and additional considerations (temp., leaks, etc...had not considered...yet!).
 

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