Pressure required to move a liquid

Click For Summary

Discussion Overview

The discussion revolves around the calculation of the air pressure and volume required to move water from one container to another using air pressure. The scenario involves a full container of water and an empty container positioned higher, with a hose connecting them. Participants explore the necessary pressure and volume of air needed to achieve this transfer, considering various factors such as flow rate and pressure conditions.

Discussion Character

  • Exploratory
  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant calculates that 2 pounds of pressure should be sufficient to raise water 4.5 feet, but expresses confusion over the volume of air needed.
  • Another participant suggests that the speed of water flow must be determined to calculate the necessary air pressure.
  • A specific flow time of 2 minutes is proposed by a participant as a basis for calculations.
  • Bernoulli's principle is mentioned as a potential method to find the required pressure, with a willingness to work with formulas expressed by a participant.
  • One participant clarifies that their primary interest is in the volume of air required rather than just pressure, indicating a desire for a continuous air addition method.
  • Another participant discusses the need to displace one cubic foot of water with air at 1.136 atmospheres of absolute pressure, questioning how much room pressure air would be necessary.
  • A participant suggests that a previous equation was incorrect and emphasizes the importance of considering the top surface of the water for calculations.
  • There is a suggestion that the calculation could be simplified to 1 X 1.36 = 1.36 cubic feet, with acknowledgment of the potential complexities regarding adiabatic versus isothermal compression.

Areas of Agreement / Disagreement

Participants express differing views on the calculations and methods to determine the necessary air pressure and volume. There is no consensus on the correct approach or final answer, as various interpretations and assumptions are presented.

Contextual Notes

Participants mention factors such as flow rate, temperature changes, and the importance of the water's surface level, indicating that assumptions and definitions may vary among contributions.

KenR
Messages
6
Reaction score
0
I have a container that measures 1 cubic foot and is full of water. I have another empty container that is 4.5 feet higher than the empty container. The full container has a fluid outlet on the bottom, and an air inlet on the top. A hose (1 inch diameter, 4.5 feet long) connects the fluid outlet to the empty container. I want to know how much air I need to add to the full container to move all of the water out of the full container. I tried figuring this out, but my answer is clearly incorrect.

I reasoned that since 1 pound of pressure is required to raise the water 2.31 feet, 2 pounds of pressure should be sufficient to accomplish the job. Next (based on this thread: https://www.physicsforums.com/threads/volume-and-pressure.87911/) I calculated that (assuming no temperature change) it would take 2/14.7*1=0.136 cubic ft. This does not make sense, as it would not even fill the container, let alone pressurize it.
 
Physics news on Phys.org
You first have to decide how fast you want the water to flow from the lower tank to the upper tank . Once you have that information you can determine the necessary air pressure .
 
Speed is not important to the practical application, but if it is required to calculate an answer let's assume 2 minutes.
 
Bernoulli's principle can be used to find the pressure needed . Are you happy working with simple formulas ?
 
I think so. Certainly willing to try.
 
Note to Nidium. I am not so much interested in pressure as I am in volume of air required. I don't want to pressurize the container and then open a valve. I want to add air to the system and as the air is added, the liquid moves. I do recognize that it is necessary to first calculate the pressure required, and then from that the volume.
 
KenR said:
I calculated that (assuming no temperature change) it would take 2/14.7*1=0.136 cubic ft.
0.136 atmospheres of pressure is required, yes. 0.136 atmospheres more than ambient, to be precise. One assumes that the empty container has a vent, so it is under 1 atmosphere of pressure already.

So you need to displace one cubic foot of water with air that will end up at 1.136 atmospheres of absolute pressure. How many cubic feet of room pressure air would you expect that to take.?
 
Your equation is just upside down, that's all that is wrong with the second part.

For the first part, remember that it is the top surface of the water that matters, not the bottom surface.
 
Jbriggs, Would it be as simple as 1 X 1.36 = 1.36 cubic feet?
 
  • #10
KenR said:
Jbriggs, Would it be as simple as 1 X 1.36 = 1.36 cubic feet?
Yes. But @russ_watters makes a good point about the water levels.

One could quibble about adiabatic versus isothermal compression as well.
 
  • #11
Thanks everyone. This is a great resource. It looks like my idea for a refueling system is feasible.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 40 ·
2
Replies
40
Views
5K
  • · Replies 32 ·
2
Replies
32
Views
12K
  • · Replies 33 ·
2
Replies
33
Views
6K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 14 ·
Replies
14
Views
4K
Replies
19
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 46 ·
2
Replies
46
Views
5K