Calculate Coefficient of Friction for a 200kg Load on a Horizontal Plane

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To calculate the coefficient of friction for a 200kg load on a horizontal plane, the weight is determined using W=mg, resulting in a normal force of 1960N. A horizontal force of 196N is required to overcome friction, leading to the equation F(friction)=(mu)N. The initial calculation mistakenly suggested that mu equals 0.2, but it was corrected to 0.1 after identifying a typographical error. The correct coefficient of friction is therefore 0.1. This calculation illustrates the relationship between force, weight, and friction on a horizontal surface.
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Homework Statement



A load of 200kg rests on a horizontal plane.A horizontal force of 196N is needed to overcome friction.Find the coefficient of friction

Homework Equations


F(gravity)=W=mg
F(friction)= (mu)N


The Attempt at a Solution



W=mg
W=200(9.8)=1960N
This then is the F(normal) also.

Now
F(fric)=(mu)N
196=(mu)1960
mu=196/1960=0.2=answer

thanks in advance
 
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Looks good.
 
looks good... except for the part 196/1960 = ... well not .2 XD
 
Oops >.<
 
Thanks for all the help.Yes, it was a typo...i know it should be 0.1 :)
 

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