Calculate concentration of halfcell

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The discussion revolves around calculating the concentration of Cd2+ in a voltaic cell using the Nernst equation, given the initial cell potential and the concentration of Mn2+. The user sought guidance on how to approach the problem, providing specific half-reaction equations and standard electrode potentials. After some interaction, the user confirmed they solved the problem independently. The conversation highlights the importance of understanding electrochemical principles and applying the Nernst equation for concentration calculations. The thread concludes with the user expressing gratitude for the assistance received.
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Hello
Im completely stuck on this question and don't know where to begin or what to do.. and help or guidance is appreciated:

A voltaic cell at 25oC consists of Mn/Mn2+ and Cd/Cd2+ half-cells with an initial cell potential of +0.768 V. The [Mn2+] concentration is 0.500 M. Use the Nernst equation to calculate the [Cd2+] concentration in the Cd/Cd2+ half-cell.
Cd+2(aq) + 2e- = Cd(s) . . . . . Eo = -0.40 V

Mn+2(aq) + 2e- = Mn(s) . . . . . Eo = -1.18 V

a. 0.010 M
b. 0.050 M
c. 0.20 M
d. 0.5
e. 0.25
its an online assignment and its due at 6am so any help soon is appreciated THANKS
 
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got it!

thnx for lookin but we figured it out :)
 
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