Calculate Current in B-Field Loop @t=8s

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A circular loop with a radius of 0.25 m and 17 turns is placed in a magnetic field that varies with time, specifically B(t) = 0.01 t^3 T/s^3. At t = 8 seconds, the induced electromotive force (emf) is calculated to be approximately 6.41 V, and the resistance of the loop is determined to be about 2.94 Ohms. The current at this moment is found to be -2.18 A, indicating a clockwise direction. The total charge passing through the windings from t = 0 to 15 seconds is calculated using the relationship Q(t) = 0.0668t^3, resulting in 225.60 C at t = 15 seconds. The calculations demonstrate the relationship between magnetic flux, induced emf, and current in the loop.
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A circular loop with radius a = 0.25 m and N = 17 turns lies in the plane of the page (x-y plane). The wire used in constructing the loop has a resistance per unit length of dR/dl = 0.11 W/m.

A spatially uniform magnetic field points in the -z direction (into the page). In the interval between t = 0 and 15 s, the strength of this field varies according to the expression B(t) = 0.01 t^3 T/s3.

Calculate the current in the windings at t = 8 s. (Give the magnitude and algebraic sign - let a current that is clockwise in the view shown in the figure defined to be positive.)

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First, I calculated the B-field @ t=8, which turned out to be 6.408849013 V.
Now, to find the current, I'm advised to write the equivalent Kirchoff's loop equation. I'm having a hard time doing this, because I'm given dR/dI, instead of just R. Since it's "resistance per unit length", I multiplied by 2pi*RN. What happens then?
 
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What is the general expression for finding out induced emf wrt flux change ?
What is the value of induced emf at t = 8sec

Multiplying by 2pi*r*N would give you total resistance R.
Now you have induced emf and resistance. How will you find the current ?

Arun
 
Huh. I swear I tried that to find R and therefore I. But this time it worked, actually. :)

Now I'm asked, "In the time interval between 0 and 15 s, how much electrical charge passes any given point in the windings? (Give magnitude only.)"

I have...
emf @ t=8 : dPhi/dt = 6.408849013 V
I @ t=8 : dQ/dt = -2.181818 A
R = 2.937389131 Ohms

Q = -2.181818t, right?
So, Q(15) - Q(0) = -2.181818 * 15 = 32.72727 C, but that was too easy and wrong. Where should I be headed?

EDIT:

I also tried this:
Since I know that Phi = BA = 0.01t^3 * 2pi * 0.25^2 * 17 (the # of windings) = 0.0333794219t^3
Then I have this equation:
d(0.1963495408t^3)/dt = 2.937389131 * dQ/dt.
I integrate both sides w/ respect to t, and I get
0.1963495408t^3 = 2.937389131*Q(t)
Then Q(t) = 0.0668449198t^3
Evaluating Q(t) for t=0..15, I get
0.0668449198(15)^3 = 225.6016042 C, which is still wrong.

EDIT:

I got it :)
 
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