Calculate Distance for Bob to Stop at Stop Sign

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Bob's car decelerates uniformly from 20.0 m/s to 0.0 m/s over 4.0 seconds, requiring a stopping distance of 40 meters before the stop sign. The calculation involves using the average velocity formula, where the distance is derived from the initial and final velocities. The acceleration is calculated as -5 m/s², confirming the stopping distance. The solution is validated by multiple contributors, affirming that the approach using average velocity is correct. Therefore, Bob must apply his brakes 40 meters before the stop sign.
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Homework Statement


When Bob applies the brakes to his car, it slows uniformly from 20.0 m/s to 0.0 m/s in 4.0 s. How many meters before a stop sign must he apply his brakes in order to stop at the sign?


80 m

60 m

40 m

20 m



Homework Equations



d=(20+0)/2(4)
d= 40 m

The Attempt at a Solution



Bob needs 40 m to stop his car.

Would that be correct?
 
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Yes.
 
Distance = ??
Time = 4s
Velocity initial = 20m/s
Velocity final = 0m/s
Acceleration = ??

A = Vf-Vi / T
A = -20 / 4
A = -5m/ss

D = ViT + ATT/2
D = (20)(4) + (-5)(4)(4) / 2
D = 80 + -40
D = 40m

yes, you're correct
 
@ billybobay,

It's perfectly fine to work it out the way you did, using average velocity.
 
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