Calculate Euler Buckling Load with Different End Fixity Conditions

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The discussion focuses on calculating the Euler buckling load for a steel rod with specific dimensions and pinned end conditions, resulting in a load of 259.1 kN. The user seeks to explore three additional end fixity conditions: pinned-fixed, fixed-fixed, and fixed-free, each affecting the critical buckling load differently. The equations for each condition are provided, indicating how the load varies based on the end fixity. Assistance is requested for performing the calculations for these scenarios. The conversation emphasizes the importance of understanding how end conditions influence buckling behavior.
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a steel rod, 40mm in diameter and 1.00m long is pinned at each end

calculate the euler bucking load

Answer:

using PE = pie sqaured 210x10cubed kN/mm x 1.25 x 10power 5mm to the 4 divided by 1000mm sqaured

=259.1kN

b) indentify three other possible end fixity conditions for the rod and demonstrate how the Euler buckling load will be effected in each case

i have pinned -fixed, PE=2.04pie sqaured EI divided by L sqaured

fixed -fixed , PE= 4pie sqaured EI dived by L sqaured
and fixed free, PE= quater pie sqaured EI divide by L sqaured

can someone help with question b.

thnak you
 
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What sort of help are you looking for? You've identified 3 other end conditions and noted how it affects the critical buckling load.
 
believe i have to do the calculations too for the equations
 
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