Calculate Frictional Force for 800N Force on 100kg Block

AI Thread Summary
An 800N force is applied to a 100kg block on an incline, with a weight component of 500N acting down the slope. The frictional force is calculated using the equation Ff = Fi - Wx, resulting in a frictional force of 18N. The discussion emphasizes that the frictional force is determined by the normal force multiplied by the coefficient of friction (µ). Participants clarify the correct relationship between these variables to ensure accurate calculations. Understanding these principles is essential for solving problems involving friction on inclined planes.
emilyn
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1. A force of 800N parallel to the plane is applied to a 100kg block on the plane to push it up the plane. If the component of the weight down the incline plane is 500 N, what is the frictional force?



2. Frictional force = u.Normal Force



3. Fi = Wx + Ff
Ff = Fi - Wx
Ff = 18 N
 
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Welcome to PF!

emilyn said:
Frictional force = 1/Normal Force
…
Fi = Wx + Ff
Ff = Fi - Wx
Ff = 18 N[/b]

Hi emilyn! Welcome to PF! :smile:

Nooo … frictional force = normal Force times coefficient of friction (µ).

(or µ = frictional force/normal force :wink:)

Try again! :smile:
 

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