Calculate Horizontal Force at an Incline

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To calculate the horizontal force on a block being pulled at an incline, the force exerted by the cord must be broken down into components. The gravitational force acting on the block is 34.7 N, derived from its mass and gravity. The acceleration of the block is calculated as 3.36 m/s² using the total force divided by mass. To find the horizontal force, the horizontal component of the pulling force must be determined using trigonometric functions. Properly resolving the force into its components is crucial for accurate calculations.
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[SOLVED] Force at an Incline

A 3.54 kg block located on a horizontal frictionless floor is pulled by a cord that exerts a force F=11.90 N at an angle theta=16.0o above the horizontal, as shown. What is the speed of the block 6.10 seconds after it starts moving?

Fgravity = (3.54*9.8) = 34.7N

F/m = a ... 11.90/3.54 = 3.36 m/s^2

How would I calculate the horizontal force?
 
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First i think that the way you solved for your acceleration was wrong because if it is at an angle, you will need to find the components and set that to Fnet. For example, since the cord is exerting a force at 11.90 N at 16.0o that will be your Ft. you will need to find Ftx after that.
 

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