Calculate Interferometer Fringe-Shifts for 10.0cm Chamber with 600-nm Light

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To calculate the fringe shifts in a Michelson Interferometer with a 10.0cm chamber and 600-nm light, the refractive index of air (1.00029) is considered. The initial calculation involves determining the number of wavelengths in the chamber, which is done by using the formula m = 2xn/λo, resulting in 333430 wavelengths. When the air is evacuated, the refractive index changes to 1, necessitating a subtraction of the wavelengths encountered in air from those in a vacuum. This difference directly correlates to the number of fringe shifts observed. The discussion confirms that the approach to the problem is correct and provides clarity on the calculation process.
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Suppose we place a chamber 10.0cm long with flat parallel windows in one arm of a Michelson Interferometer that is being illuminated by 600-nm light. If the refractive index of air is 1.00029 and all the air is pumped out of the cell, how many fringe-pairs will shift by in the process?

for this problem, i can't visualize the design of the interferometer at all. All I'm thinking is that m=finge-pairs?, so m=2xn/λo = 333430?

Any help would be good...at least let me know if I'm going to the right direction or not.
 
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Your in the right direction, you calculated the number of wavelengths found when traversing the length of the chamber, twice. Now just subtract the number of wavelengths you would encounter by evacuating the chamber. (Index = 1) This will give you the change in wavelengths which happens to be the number of fringe changes. Hope this helps.
 
thanx a lot jisland85...i understand now. :)
 

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