Calculate Launch Velocity: Spring Force with 80kg Mass and 2kg Object

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To calculate the launch velocity of a 2.0 kg object using a spring, first determine the spring constant (k) using the initial scenario with the 80.0 kg mass that compresses the spring by 20 cm. The relationship between gravitational potential energy and spring potential energy is given by the equation mgh = 1/2 kx^2, where h is the height change and x is the spring compression. In this case, x is the compression of the spring, and h is equivalent to x due to the spring's compression. After finding k, apply the conservation of mechanical energy to find the launch velocity of the 2.0 kg object when the spring is compressed by 5.0 m. Understanding these principles will allow for the correct calculation of the launch velocity.
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When a 80.0kg mass is placed (not dropped) on topof a spring, the spring is depressed by 20 cm. The same spring is then used to launch a 2.0 kg object vertically. If the spring is compressed 5.0 m by pushing it down, and the object is then placed on top and the spring released, what will be the launch velocity of the 2.0kg object? Draw and label the force diagram as part of your answer.

I do not really ge twhat I am supposed to do here and I have no clue where to start. Any help would be greatly appreciated!
 
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try using energy to solve for the spring constant.
 
But how would I find the energy?
 
mgh = \frac {1}{2} kx^2
 
But what would be my h and what would be my x?
 
I am not given the h or the x am I?
 
The x is the amount that the spring is compressed. In this case the h is the same as the x, because the only change in the masses hight is because off the compression of the spring.
 
Ok thanks!
 
Wait, am I using the 8o.o kg and the 20cm or the 1.0kg and the 5.0m?
 
  • #10
80.0kg and the 20cm
 
  • #11
so then I get 68.6 for k but then what do i do with that?
 
  • #12
Force = kx
F/x = k

what is the Force...check your units.
 
  • #13
I am not sure what you mean?
 
  • #14
once you find the spring constant, you can use it for the second part of the problem.
 
  • #15
Hint: Conservation of mechanical energy.
 
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