Calculate Lift Force of 4510 kg Helicopter Accelerating Upward

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To calculate the lift force exerted by the air on a 4510 kg helicopter accelerating upward at 2.1 m/s², Newton's Second Law is applied. The net force (Fnet) is determined using the equation Fnet = m * a, resulting in 9471 N. However, this value only accounts for the acceleration; the total lift force must also counteract the weight of the helicopter. The weight is calculated as W = m * g, where g is approximately 9.81 m/s², resulting in a weight of about 44281 N. Therefore, the total lift force required is the sum of the weight and the net force, equating to approximately 53752 N.
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A 4510 kg helicopter accelerates upward at 2.1 m/s^2. What lift force is exerted by the air on the propellers?

The answer is in Newtons.

If you can give me an equation, that would be great. Thanks
 
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What have you tried? I would think your book or instructor would have given you some equations of motion. Nothing?
 
I looked through all equations in the chapter and none seem to fit.
 
How about Newtons' Second Law of motion?
 
k Newton's second law

a = Fnet/m

so 2.1 = Fnet/4510 and for Fnet you get 9471 but what then
 
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