Calculate Magnetic Induction in Cylindrical Hole w/ Uniform Current

Crazy Gnome
Messages
13
Reaction score
0
Question: An infinite cylindrical wire with radius 2R caries a uniform current density J=Jz, except in an infinite cylindrical hole parallel to the wires axis. The hole has a radius of R and is tangent to the exterior of the wire. Calculate the magnetic induction B everywhere inside the hole.

It would seem to me that according to Ampere's law B inside the cavity would just be 0 because there is no enclosed current. What am I missing? And the reason I doubt my answer so much is that he then wants us to plot B as a function of radius in the hole and I can't imagine plotting 0 was his intention.
 
Physics news on Phys.org


Crazy Gnome said:
Question: An infinite cylindrical wire with radius 2R caries a uniform current density J=Jz, except in an infinite cylindrical hole parallel to the wires axis. The hole has a radius of R and is tangent to the exterior of the wire. Calculate the magnetic induction B everywhere inside the hole.

It would seem to me that according to Ampere's law B inside the cavity would just be 0 because there is no enclosed current. What am I missing? And the reason I doubt my answer so much is that he then wants us to plot B as a function of radius in the hole and I can't imagine plotting 0 was his intention.

You are correct in doubting your answer, which is wrong.
Here's a hint to solving the problem: imagine how you can produce that hole by superposing two cylinders.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top