Calculate Marginal Product from APL: 8 Workers Hired

  • Thread starter Thread starter joe342
  • Start date Start date
  • Tags Tags
    Marginal Product
joe342
Messages
5
Reaction score
0
Consider the function APL=\frac{\sqrt[4]{L}}{L}, where L is the number of workers. The company has just hired 8 workers. What is the marginal product of the labor?I know that if I had the total product I could differentiate it and get the marginal product, but it's the average product that is given.APL=\frac{\sqrt[4]{8}}{8}=\frac{1,68}{8}=0,21

How do I get to MP from here?
 
Physics news on Phys.org
joe342 said:
Consider the function APL=\frac{\sqrt[4]{L}}{L}, where L is the number of workers. The company has just hired 8 workers. What is the marginal product of the labor?


I know that if I had the total product I could differentiate it and get the marginal product, but it's the average product that is given.


APL=\frac{\sqrt[4]{8}}{8}=\frac{1,68}{8}=0,21

How do I get to MP from here?

Please do not use undefined abbreviations. What is AP? What is MP? I might be able toe guess, but I should not have to!
 
Ray Vickson said:
Please do not use undefined abbreviations. What is AP? What is MP? I might be able toe guess, but I should not have to!
joe342 said:
I know that if I had the total product I could differentiate it and get the marginal product, but it's the average product that is given.

Im sorry, I thought I made it clear here. Average product of labor and marginal product of labor.
 
joe342 said:
Im sorry, I thought I made it clear here. Average product of labor and marginal product of labor.

OK, so what is the actual definition of average product of labor in terms of the marginal product function f(L)? Understanding that relationship is step 1 in the solution procedure.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top