Calculate Mass of Sphere: ρ0 & R

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The discussion centers on calculating the mass of a sphere with a density function ρ(r) = ρ0(1 − r/R). The approach involves integrating the mass of spherical shells from the center to the radius R, using the formula dm = 4πr²(1 - r/R)ρ(r)dr. Participants express confusion about the integration process, particularly how to handle the term (1 - r/R) during integration. The integration ultimately leads to the expression m = 4πρ0 multiplied by the integral of (r² - r³/R) from 0 to R, resulting in a final mass calculation. Clarification on the integration steps is requested to ensure accurate results.
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Homework Statement



The density of a sphere of radius R as a function of distance from the centre r is ρ(r) = ρ0(1 − r/R)
What is the mass of the sphere in terms of ρ0 and R?

Homework Equations



Volume of a Sphere=(4/3)piR3


The Attempt at a Solution



I'm somewhat confused by the question. To my understanding, I can determine the mass of the sphere by integrating from 0 to radius R. I would consider a spherical shell a distance r from the center and of thickness dr. Thus I integrate from 0 to R and get something like 4pir2(1-r/R)ρ(r)dr, which is the mass of the sphere. But I'm not sure if that's what is needed. Any ideas?
 
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dm = 4pir2(1-r/R)ρ(r)dr
Complete the integration. So
m = 4*pi*rho* intg(r^2*dr - r^3*dr/R) from zero to R.
 
rl.bhat said:
dm = 4pir2(1-r/R)ρ(r)dr
Complete the integration. So
m = 4*pi*rho* intg(r^2*dr - r^3*dr/R) from zero to R.

Huh, I'm not quite sure how the integration with (1-r/R) works...R would be the radius, and r would be the distance from centre...care to explain?
 
You have to integrate [ intg(r^2*dr - r^3*dr/R)] between 0 to R.
It is equal to [R^3/3 - R^3/4]
 
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