Calculate maximum allowable stress

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The discussion focuses on calculating the maximum allowable stress for a ceramic plate designed to withstand a tensile load of 177.92 kN. The plate, made from sialon, requires determining its minimum thickness and maximum allowable design stress, with a fracture toughness (Kic) of 9.9 MPa√m. Non-destructive testing methods using x-ray radiology will be employed to detect flaws larger than 0.05 cm. A participant expresses difficulty in incorporating thickness into the stress calculations, noting that stress in a plate differs from direct tension formulas. The conversation encourages collaboration to clarify these calculations.
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1. A decision has been made to make a plate out of an advanced engineering material ceramic that has better high temperature and wear properties than alloys. The plate must withstand a tensile load of 177.92kN. The part will be non-destructively tested to ensure that no flaws are present that might cause failure. A company offers non-destructive testing methods using x-ray radiology that can detect flaws larger than 0.05 cm. Assume Y=1.0. Determine the minimum thickness for a 7.5mm wide plate made of sialon (Kic = 9.9 Mpa\sqrt{}m) . Also calculate the maximum allowable design stress.



2. Kic = Y*\sigma*sqrt{\pi*a}

\sigma allowable = FORCE/AREA




3. I just don't see how to factor in the 'thickness' into my calculations and so i cannot begin with my calculations. Can someone help me with this please.
 
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