Calculate Percent Volume Submerged: Buoyancy Problem

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To calculate the percentage of volume submerged for the wood in the ocean, the density of the wood (1.428 x 10^-3 kg/m3) is compared to the density of seawater. Since the density of the wood is less than that of seawater, it will float, but the exact percentage of volume above water can be determined using the principle of buoyancy. The submerged volume is equal to the volume of water displaced, which is influenced by the object's density relative to the fluid. If the wood's density were greater than seawater, it would sink, but in this case, it will float with a portion submerged. Understanding these principles clarifies how buoyancy and displacement affect floating objects.
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A rectangular piece of wood ( 5.0 X 4.0 X 3.0 cm) and mass 42g is thrown into the oceon, how do i calculate the percentage of volume floating above the water?
 
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what determines if something floats?

ocean
 
the density is 1.428 X 10^-3 kg/m3 for the wood, so it will float right completely above the ocean surface?
 
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is this right-??

Volume submerged = Density of wood / Density of oceon water?
 
have you ever seen something float right on the ocean surface?
 
the submerged volume = the volume of water displaced.
right?
if you put a rock in a container of water, the water level rises.

now, what does displacement have to do with floating?
 
in this case i got the density of wood more than that of that oceon so i think it will sink!
 
have you ever seen wood sink?
 
how did you get the density for wood? do you have the right units?
 
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