Calculate power with v on inclined plane with miu

AI Thread Summary
A user seeks help calculating the power exerted while dragging a 130 kg object down a 23-degree inclined plane at a speed of 1.40 m/s, with a friction coefficient of 0.800. Initial calculations yield an incorrect power output of 134 W, prompting a reevaluation of the frictional force. After correcting the frictional force to 750.5 N and recognizing that the object moves at constant speed, the user determines that an additional force of 449 N is needed to overcome friction. The final power calculation, based on this force and the velocity, leads to the correct answer of 629 W. The discussion highlights the importance of accurately calculating friction and understanding forces on an inclined plane.
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Homework Statement



please advise how to solve. seems i can't without d given, or t!

a man drags a 130 kg object down an inclined plane at a speed of 1.40m/s
The coefficient of friction between the object and the inclined plane is 0.800 and the angle of inclination with the horizontal is 23 degrees. What is the amount of power this man expends in dragging the object?

Homework Equations


Work = F d
Work = F cos theta d

Power = Work/time
Power = F v

Work = change in kinetic energy

The Attempt at a Solution



F friction = 0.8 ( mg cos 23) = 95.7N
Power = F.v = 95.7 * 1.4 =134W
but i know this answer is wrong tho, the answer given is 629 W.

please help me get this before my exam! many thx
 
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Welcome to PF.

I would suggest recalculating your frictional resistance. That looks a little light.
 
Thanks for the heads up, i didn't multiply with gravity as i should have - the friction force corrected is 750.5N

I think the parallel and net forces also play a role here in resisting friction. I can't seem to get the applied force down the inclined plane.

the parallel force along the incline is mg sin 23 = 497.8N

This should reduce the force acting down the incline ( F friction - f parallel) = 252.7 N
but friction is still more and it should not move.

how can i find the force needed to drag it down the incline at v= 1.4m/s? won't i need acceleration to find the net force?
 
There is no acceleration as it is at constant speed of 1.4 m/s.

So yes you do subtract the Sin23*130*9.8 from the frictional maximum need to push it along, because as you have figured it is the net force that HE supplies that is doing the work that they ask for.
 
I would note however that :

.8 * 130 * 9.8 * cos23 = 938.1785
 
omg, i got it! no net force, he just need to apply additional force of 449 N to overcome friction and move it at a constant speed. Multiply this force and velocity will give me the Power ! thanks :D
 
yup caught that too! it was messing up my calculations! thanks so much lowlypion! :D
 
solved!
 

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