Calculate Relative Speeds of Moving Objects for Twin Paradox

  • Thread starter Thread starter Alkatran
  • Start date Start date
Alkatran
Science Advisor
Homework Helper
Messages
959
Reaction score
0
I understand the ideas behind relativity (4d space time, different speeds see different slices of it, what not), but I've never done the math.

If I have something traveling at v1 relative to some frame, and another thing traveling at v2, what is v2 transformed into the reference frame moving at v1?

I'm trying to model the twin paradox in a computer program.

Oh, and how do I calculate the slope of a reference frame relative to another reference frame? Is it just (+-)gamma?
 
Physics news on Phys.org
You need to use the velocity-transformations.
 
Alkatran said:
If I have something traveling at v1 relative to some frame, and another thing traveling at v2, what is v2 transformed into the reference frame moving at v1?
Suppose you're on a train moving with velocity u relative to the ground, and you walk forward with velocity v relative to the train, your velocity relative to the ground is not u+v but (u+v)/(1+uv). (I'm using units in which c=1. Otherwise this would be (u+v)/(1+uv/c²).)

This is the relativistic velocity addition law.

You seem to be asking for a slightly different version of it (if I understand you correctly). Suppose a train is moving with velocity v1 relative to the ground, and some guy is walking with speed v2 relative to the ground, then what is this guy's speed relative to the train?

According to the velocity addition law it is (-v1+v2)/(1+(-v1)v2).

Alkatran said:
Oh, and how do I calculate the slope of a reference frame relative to another reference frame? Is it just (+-)gamma?
Suppose that another observer is moving with velocity v in the coordinate system where you are stationary at the origin, and that you both measure time from an event when both of your origins were at the same place, then his t axis in a spacetime diagram that represents your coordinates is a line through the origin with slope 1/v (remember that t is in the "up" direction), and his x-axis is a line through the origin with slope v. Each line that is parallell to his x-axis represents a set of events that are simultaneous to him.

Note that the when the astronaut twin has changed his direction, these lines of simultaneity ("slices" of spacetime that he thinks of as space at different times) will be very different from what they were before.
 
Alkatran said:
I understand the ideas behind relativity (4d space time, different speeds see different slices of it, what not), but I've never done the math.

If I have something traveling at v1 relative to some frame, and another thing traveling at v2, what is v2 transformed into the reference frame moving at v1?

That's just a velocity subtractin problem. Classically the answer is v2-v1, relativistically the answer is (v2-v1)/(1+v1*v2/c^2)

I'm trying to model the twin paradox in a computer program.

Oh, and how do I calculate the slope of a reference frame relative to another reference frame? Is it just (+-)gamma?

That would probably depend on how you draw the reference frame. In any event, you should be able to figure it out from the Lorentz transform.

I prefer the following version

[edit! Major ooops!]

x' = gamma*(x - v t)
t' = gamma*(t - v x)

where
gamma = 1/sqrt(1-v^2)

the inverse of which is

x = gamma*(x' + v t')
t = gamma*(t' + v x')

[end edit]

but note that the require that you use "relativistic" units, where time for example might be measured in seconds and distance in light seconds, or time in years and distance in light years.
 
Last edited:
I started reading a National Geographic article related to the Big Bang. It starts these statements: Gazing up at the stars at night, it’s easy to imagine that space goes on forever. But cosmologists know that the universe actually has limits. First, their best models indicate that space and time had a beginning, a subatomic point called a singularity. This point of intense heat and density rapidly ballooned outward. My first reaction was that this is a layman's approximation to...
Thread 'Dirac's integral for the energy-momentum of the gravitational field'
See Dirac's brief treatment of the energy-momentum pseudo-tensor in the attached picture. Dirac is presumably integrating eq. (31.2) over the 4D "hypercylinder" defined by ##T_1 \le x^0 \le T_2## and ##\mathbf{|x|} \le R##, where ##R## is sufficiently large to include all the matter-energy fields in the system. Then \begin{align} 0 &= \int_V \left[ ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g}\, \right]_{,\nu} d^4 x = \int_{\partial V} ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g} \, dS_\nu \nonumber\\ &= \left(...
In Philippe G. Ciarlet's book 'An introduction to differential geometry', He gives the integrability conditions of the differential equations like this: $$ \partial_{i} F_{lj}=L^p_{ij} F_{lp},\,\,\,F_{ij}(x_0)=F^0_{ij}. $$ The integrability conditions for the existence of a global solution ##F_{lj}## is: $$ R^i_{jkl}\equiv\partial_k L^i_{jl}-\partial_l L^i_{jk}+L^h_{jl} L^i_{hk}-L^h_{jk} L^i_{hl}=0 $$ Then from the equation: $$\nabla_b e_a= \Gamma^c_{ab} e_c$$ Using cartesian basis ## e_I...

Similar threads

Replies
4
Views
1K
Replies
11
Views
2K
Replies
24
Views
4K
Replies
7
Views
2K
Replies
137
Views
10K
Back
Top