Calculate Tension in 5m String Attached to 4kg Bob

AI Thread Summary
To calculate the tension in a 5 m string attached to a 4 kg bob moving in horizontal circles with a 0.6 m radius, the angle α is determined to be approximately 6.9 degrees. The correct equation for tension is T cos α = m*g, leading to T = m*g/cos α. After correcting calculations for cos 6.9 degrees, which is approximately 0.992757341, the tension is recalculated to be around 39.5 N. The initial calculation of tension at 326.6 N was incorrect due to misapplication of trigonometric functions. The final tension value confirms the need for precise angle calculations in physics problems.
John78
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Homework Statement



Calculate the tension in a 5 m string attached to a 4 kg bob that is moving in horizontal circles of 0.6 m radius.


Homework Equations





The Attempt at a Solution



α= tan-1 0.6/5
= 7 degree

T cos α = m*g

T= m*g/cosα

T=4*9.8/0.12

T=326.6 N



I just want to check whether my working is correct or not.
 
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Your equations are almost correct, however, if the angle α is 7 degrees, then cos α = cos 7 = ? But your calc for that angle is not right. It is not the tan function per your attempt...
 
so am I right in my calculations

α= sin 0.6/5
= 7 degree = 0.121869343

T cos α = m*g

T= m*g/cosα

T=4*9.8/0.121869343

T=321.65N
 
John78 said:
so am I right in my calculations

α= sin^-1 0.6/5 = sin^-1 0.12
α = 6.9 degrees[/color]

T cos α = m*g

T= m*g/cosα
yes
T=4*9.8/0.121869343
No, the cosine of 6.9 degrees is not 0.121869343
 
cos 6.9 = 0.992757341

Am I right?
 
John78 said:
cos 6.9 = 0.992757341

Am I right?
yes, so T = ?
 
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